Rohan throws a dice. Find the probability of getting: (i) an even number (ii) a prime number (iii) a natural number (iv) a 7
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I) P(an even number)- 1 - 4/6= 3/6
Ii) P( a prime number)- 1 - 4/6 = 2/6
Iii) P( a natural number) 1 - 6/6 = 1
Iiii) P ( a 7) 1- 0/6 = 0/6
Hope this helps
Pls mark me as brainiest pls pls
Ii) P( a prime number)- 1 - 4/6 = 2/6
Iii) P( a natural number) 1 - 6/6 = 1
Iiii) P ( a 7) 1- 0/6 = 0/6
Hope this helps
Pls mark me as brainiest pls pls
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