Question

if f(x-1) = x^2-4x+8, then f(x+1) = ?​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The value of f(x + 1) = x² + 4.

Step-by-step explanation:

Given, f(x - 1) = x² - 4x + 8

=> f(x + 1 - 1) = (x + 1)² - 4(x + 1) + 8

=> f(x) = x² + 2x + 1 - 4x - 4 + 8

=> f(x) = x² - 2x + 5

Now, f(x + 1) = (x + 1)² - 2(x + 1) + 5

f(x + 1) = x² + 2x + 1 - 2x - 2 + 5

f(x + 1) = x² + 4

Hence, the value of f(x + 1) = x² + 4.