if f(x)²=x²+5x-14,find f(1),f(-1),f(0),andf(2)
Answers
Answered by
6
Answer:
f(x)=x
2
−5x+1
f(2)=2
2
−5×2+1
=4−10+1
=−6+1
=−5
f(−1)=(−1)
2
−5×−1+1
=1+5+1
=7
f(
3
1
)=
3
1
2
−5×
3
1
+1
=
9
1
−
3
5
+1
=
9
1
−
9
15
+
9
9
=
9
10−15
=
9
−5
f(2)−f(−1)+f(
3
1
)=−5−7−
9
5
=−12−
9
5
=
9
−108−5
=−
9
113
Answered by
0
Answer:
f(1) = -8
f(-1)= -18
f(0)= -14
f(2)= 0
Step-by-step explanation:
Here it given the equation f(x)²=x²+5x-14,
then as we know f(1) means in equation we have to substitute value (1) at the place of x
f(x)²=x²+5x-14
f(1)²=(1)²+5(1)-14 = 1+5-14=-8
then f(1) = -8
f(x)²=x²+5x-14
f(-1)²=(-1)²+5(-1)-14=1-5-14=-18
then f(-1)= -18
f(x)²=x²+5x-14
f(0)²=(0)²+5(0)-14=-14
then f(0)= -14
f(x)²=x²+5x-14
f(2)²=(2)²+5(2)-14=0
then f(2)= 0
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