Math, asked by Nadhiya2446, 11 months ago

if f(x)=2x-1/5x-2 verify whether (fof)(x)=x.

x does not belongs to 2/5

Answers

Answered by hukam0685
36

Answer:

Yes,it is verified that fof(x)=x

Step-by-step explanation:

To verify

fof(x) = x \\  \\ if \\  \\ f(x) =  \frac{2x - 1}{5x - 2}   \:  \:  \:  \: x \neq \frac{2}{5} \\  \\  \\ fof(x) = \frac{2\big(\frac{2x - 1}{5x - 2}\big) - 1}{5\big(\frac{2x - 1}{5x - 2}\big) - 2} \\  \\ fof(x) = \frac{\big(\frac{4x - 2 - 5x + 2}{5x - 2}\big) }{\big(\frac{10x - 5 - 10x + 4}{5x - 2}\big) } \\  \\  \\ fof(x) =  \frac{4x - 5x - 2 + 2}{10x - 10x - 5 + 4}  \\  \\ fof(x) =  \frac{ - x}{ - 1}  \\  \\ fof(x) = x \\  \\

Hence proved.

Answered by pgadade496
2

Answer:

(x) = [2x – 1] / [x + 5] = y

xy + 5y = 2x – 1

xy – 2x = – 1 – 5y

x = [- 1 – 5y] / [y – 2]

y = [- 1 – 5x] / [x – 2]

= [5x + 1] / [2 – x], x ≠ 2

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