If f(x) = 2x³-13x²+17x+12, find
(i) f(2) (ii) f(-3) (iii) f(0)
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Given : If f(x) = 2x³ - 13x² + 17x + 12
(i) On putting x = 2 in f (x).
f(2) = 2(2)³ – 13(2)² + 17(2) + 12
= 2 x 8 - 13 × 4 + 17 × 2 + 12
= 16 – 52 + 34 + 12
= 62 – 52
= 10
Hence, f(2) = 10
(ii) On putting x = - 3 in f (x).
f(-3) = 2(- 3)³ - 13(- 3)² + 17 x (- 3) + 12
= 2 x (-27) - 13 x 9 + 17 x (- 3) + 12
= - 54 - 117 - 51 + 12
= - 222 + 12
= - 210
Hence, f(- 3) = - 210
(iii) On putting x = 0 in f (x).
f(0) = 2 x (0)³ - 13(0)² + 17 × 0 + 12
= 0 - 0 + 0 + 12
= 12
Hence, f(0) = 12
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