Question

If f(x+3)=2x^2-3x-1,find the value of f (x+1)​

Answer 1

Is it f (x)

Or

X+1=x+3/2x-1

Answer 2

Answer:

2$x^{2}$ - 11x + 13

Step-by-step explanation:

Given,

f(x+3) = 2$x^{2}$ - 3x -1

To find: f(x+1)

Detailed Solution:

                f(x+3) = 2$x^{2}$ - 3x -1

In the above given equation, replace x by (x-2), we get:

x → x - 2

f(x-2+3) = 2$(x-2)^{2}$ - 3(x-2) - 1

f(x+1)  =  2($x^{2}$ + 4 - 4x) - 3x + 6 - 1

f(x+1) = 2$x^{2}$ + 8 - 8x - 3x + 6 - 1

f(x+1) = 2$x^{2}$ - 11x +13

Hence, the value of f(x+1) is 2$x^{2}$ - 11x +13.

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