Question

(sec 2A + 1)sec^2A =​

Answer 1

Answer:

$Sec^2A(1+Sec2A)\\=\frac{1}{Cos^2A}(1+\frac{1}{Cos2A})\\=\frac{1}{Cos^2A}(\frac{Cos2A+1}{Cos2A})\\=\frac{1}{Cos^2A}(\frac{2Cos^2A-1+1}{Cos2A}\\=\frac{1}{Cos^2A}(\frac{2Cos^2A}{Cos2A})\\=(\frac{2}{Cos2A}\\=2Sec2A$

Answer 2

Answer:

cosA(1+CosA) ans ......