Question

If f(x) = 3 + 5/x ,What number CANNOT be in the range of the function f(x)?

Please provide a valid explanation aswell.​​

Answer 1

Answer:

Please forgive me

Step-by-step explanation:

beyond 2 all the numbers

Answer 2

the domain is defined for all real values of x except for

values of x which make the denominator equal zero

to find the value that x cannot be, equate the denominator

to zero and solve

solve

2

x

+

1

=

0

⇒

x

=

−

1

2

←

excluded value

⇒

domain is

x

∈

R

,

x

≠

−

1

2

to find any excluded values in the range, rearrange

y

=

5

x

−

3

2

x

+

1

making x the subject

⇒

y

(

2

x

+

1

)

=

5

x

−

3

←

cross-multiplying

⇒

2

x

y

+

y

=

5

x

−

3

⇒

2

x

y

−

5

x

=

−

3

−

y

⇒

x

(

2

y

−

5

)

=

−

(

3

+

y

)

⇒

x

=

−

3

+

y

2

y

−

5

the denominator cannot equal zero

solve

2

y

−

5

=

0

⇒

y

=

5

2

←

excluded value

⇒

range is

y

∈

R

,

y

≠

5

2