if f(x+3)=f(x)+f(3) then prove that
(a) f(0) =0 (b) f(-3)=-f(3)
(c) f(6) + 2f(-3)=0
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if f(x+3)=f(x)+f(3)
then,
(a) f(0)=0
L.H.S.=f(0)= f*0 =0
R.H.S.= 0
… hence, L.H.S.=R.H.S prooved
(b) f(―3)= -f(3)
L.H.S.= f(-3)=f*-3=-f(3)
R.H.S.= -f(3)
… hence, L.H.S. =R.H.S. prooved
(c) f(6)+2f(-3)=0
L.H.S.= f*6+(-6f)= 6f-6f =0
R.H.S.=0
… hence, L.H.S. =R.H.S. prooved
hope it will help you
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