if f(x) =3e^x^2 ,then f'(x) +1/3 f(0) - f '(0) is equal to
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Answer:
2x. f(x) + 1
Step-by-step explanation:
f'(x) = (3e^x^2).(2x)
f(0)= 3
f'(0)= 0
then f'(x) +1/3 f(0)- f'(0) = (3e^x^2).(2x) + 1
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