Question

If f'(x)=3x^2+4 and f(1)=7 , find f(x).

Answer 1

Answer:

Given

f'(x) = 3x² + 4

Integrate w.r.t. x

f(x) = d/dx( 3x² + 4)

f(x) = d/dx(3x²) + d/dx(4)

f(x) = x³ + 4x

Answer 2

Answer:

Step-by-step explanation:

f(x) = (3x^3)/3 + 4x + c

f(x) = x^3 + 4x + c

f(1) = 7 <==> x=1 ; f(x)=7

f(x) = x^3 + 4x + c

7 = 1^3 + 4(1) + c

c = 2

Thus

f(x) = x^3 + 4x + 2 Answer