Math, asked by sagarsquad09, 6 months ago

if f(x)=3x-2 and fog(x)=6x-2 then find the value of x such that gof(x) =8 ​

Answers

Answered by mishraabhi8924
6

Answer:

2 is the value of x

Step-by-step explanation:

According to question

f(x)=3x-2

fog(x)=6x-2

f(g(x))=6x-2=3(2x)-2

So, we observe that g(x)=2x

Now,gof(x)=g(f(x))=2(f(x))=2(3x-2)=6x-4.

gof(x)=8

6x-4=8

6x=12

x=2

Answered by ranabikram049
0

Answer:

given , f(x)=3x-2

fog(x)=6x-2

god(x)=8

let's 3x-2+6x-2=8

9x-4=8

9x=12

x=12/9

=4/3

the value of x is 4/3

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