IF f(x)=3x^3-5x^2+7x-11, is f(0)+f(1)=f(2)?
Answers
Answered by
52
f(x)=3x^3-5x^2+7x-11
f(0)=3*0^3 -5*0^2 +7*0 -11
=0-0+0-11
= -11
now
f(1)=3*1^3 -5*1^2 +7*1 -11
=3-5+7-11
= -6
f(2)=3*2^3 -5*2^2 +7*2 -11
=3*8 - 5*4 + 7*2 -11
=24-20+14-11
=9
as per question
isf(0) +f(1)=f(2)?
-11+(-6)=9
-11-6=9
-17=9
clearly we say f(0) +f(1) is not =to f(2)
f(0)=3*0^3 -5*0^2 +7*0 -11
=0-0+0-11
= -11
now
f(1)=3*1^3 -5*1^2 +7*1 -11
=3-5+7-11
= -6
f(2)=3*2^3 -5*2^2 +7*2 -11
=3*8 - 5*4 + 7*2 -11
=24-20+14-11
=9
as per question
isf(0) +f(1)=f(2)?
-11+(-6)=9
-11-6=9
-17=9
clearly we say f(0) +f(1) is not =to f(2)
Answered by
0
Answer:
No
Step-by-step explanation:
Given;
f(x)=3x^3-5x^2+7x-11
Now;
f(0)=3*0^3 -5*0^2 +7*0 -11
=0-0+0-11
= -11
f(1)=3*1^3 -5*1^2 +7*1 -11
=3-5+7-11
= -6
f(2)=3*2^3 -5*2^2 +7*2 -11
=3*8 - 5*4 + 7*2 -11
=24-20+14-11
=9
f(0) +f(1)=f(2)?
-11+(-6)=9
-11-6=9
-17=9
we say that
f(0) +f(1) is not = f(2)
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