If f(x)=3x^4-5x^2+9 find f(x-1)
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hi mate,
solution:
Substituting x-1 in place of x
f(x-1)=3(x-1)^4–5(x-1)^2+9
(a-b)^4=a^4–4a^3b+6a^2b^2–4ab^3+b^4
=3(x^4–4x^3+6x^2-4x+1)-5(x^2–2x+1)+9
=(3x^4–12x^3+18x^2–12x+3)-5x^2+10x-5+9
=3x^4–12x^3+13x^2–2x+7
i hope it helps you
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