In a fix time a car travel 210 kmspeed 60 km h if the speed of car is increased by 20 kms how much more distance it will be cover in the same time
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Distance/speed = time
Case 1 :
D= 210 km
S = 60km/h
T = D/S = 210/60 = 3. 5 h
Case 2 :
NOW THE SPEED IS INCREASED BY 20 km/h
New Speed = 60+20 = 80 km/h
T = 3. 5 h
Distance = S*T = 80 *3. 5 = 280 km
More distance covered in the same time =
280 - 210 = 70 km
Case 1 :
D= 210 km
S = 60km/h
T = D/S = 210/60 = 3. 5 h
Case 2 :
NOW THE SPEED IS INCREASED BY 20 km/h
New Speed = 60+20 = 80 km/h
T = 3. 5 h
Distance = S*T = 80 *3. 5 = 280 km
More distance covered in the same time =
280 - 210 = 70 km
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