Question

If f(x)=5x3+4x2−13x−25f(x)=5x3+4x2−13x−25  and f(x−3)=5x3−41x2+98x+kf(x−3)=5x3−41x2+98x+k , then k=​

Answer 1

Answer:

K = -229

Step-by-step explanation:

f(x)= 5x3+4x2−13x−25    → (1)

f(x−3)=5x3−41x2+98x+k → (2)

# apply x = 0 in  (1)

so,

f(0) =   5x3+4x2−13(0)−25

f(0) =   15 + 8 - 0 - 25

f(0) =  23- 25

f(0) = -2 → (3)

# apply x = 3 in  (2)

so,

f(3-3) = 5x3−41x2+98(3)+k

f(0) = 15 - 82 + 294 + k

f(0) = 227 + k →(4)

# compare (3) and (4)

so,

227 + k = -2

k = -2 -227

k = -229