If f(x)= a cos(bx + c)+d, then range of f(x) is
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Answer:
f(x)=a cos(bx+c)+d
Range=[d-a,a+d]
Step-by-step explanation:
Range of cos thetha is [-1,1]
Let theta be bx+c
-1 ≤ cos thetha ≤1
-1 ≤ cos(bx+c) ≤1
-a ≤ acos(bx+c) ≤a
-a+d ≤ acos(bx+c)+d ≤ a+d
Range=[d-a,a+d]
hope it helps
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