If f(x) = (a-x^n)^1/n , where a>0 and n € N ,then f(x) is equal to
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you did mistake in typing, question should be -----> If f(x) = (a-x^n)^1/n , where a>0 and n € N ,then f(f(x)) is equal to
given,![f(x)=\sqrt[n]{a-x^n} f(x)=\sqrt[n]{a-x^n}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5Bn%5D%7Ba-x%5En%7D)
now,![f(f(x))=\sqrt[n]{a-\{\sqrt[n]{a-x^n}\}^n} f(f(x))=\sqrt[n]{a-\{\sqrt[n]{a-x^n}\}^n}](https://tex.z-dn.net/?f=f%28f%28x%29%29%3D%5Csqrt%5Bn%5D%7Ba-%5C%7B%5Csqrt%5Bn%5D%7Ba-x%5En%7D%5C%7D%5En%7D)
=![\sqrt[n]{a-a+x^n} \sqrt[n]{a-a+x^n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba-a%2Bx%5En%7D)
=![\sqrt[n]{x^n} \sqrt[n]{x^n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D)
= x
hence, f(f(x)) = x
given,
now,
=
=
= x
hence, f(f(x)) = x
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x
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