If f(x) = ax + bx² + c is an even function, then c =
a) 0
b) 1
c)-1
d) any real number
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Answer:
d
Step-by-step explanation:
if f(x) = f (-x) then f (x) is called a even function.
given that f(x) =ax^2+bx+c is even function
a(-x)^2+b(-x)+c = ax^2+bx+c
ax^2-bx+c = ax^2+bx + c
2bx =0
,therefore c may be any real number
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