Math, asked by vikasa89, 8 months ago


If f(x) = ax + bx² + c is an even function, then c =
a) 0
b) 1
c)-1
d) any real number



plz fast if any one keep correct answer they will be marked as brainliest​

Answers

Answered by arvardhan25
2

Answer:

d

Step-by-step explanation:

if f(x) = f (-x) then f (x) is called a even function.

given that f(x) =ax^2+bx+c is even function

a(-x)^2+b(-x)+c = ax^2+bx+c

ax^2-bx+c = ax^2+bx + c

2bx =0

,therefore c may be any real number

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