If f(x)=b(x-a)/b-a - a(x-b)/b-a. Prove f(a+b)=f(a)+f(b)
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f(x)= b(x-a)/b-a - a(x-b)/b-a=bx-ab-ax+ab/(b-a)
=bx-ax/(b-a)=x(b-a)/(b-a)=x
hence
f(a)=a
f(b)=b
f(a+b) =a+b
f(a)+f(b)=a+b=f(a+b)
=bx-ax/(b-a)=x(b-a)/(b-a)=x
hence
f(a)=a
f(b)=b
f(a+b) =a+b
f(a)+f(b)=a+b=f(a+b)
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1
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