Question

If f(x) = e^x g(x), g(0) = 2, g'0) = 2 then f'(0) is?​

Answer 1

Answer:

4

Step-by-step explanation:

f(x)=e^xg(x)

f(0) = e^0g(0)

f(0) = 1×2. coz. g(0)=2

f(0) =2

f'(x) = e^(x) g(x) + e^x g'(x)

f'(x) = e^(x) { g(x) + g'(x) }

f'(0) = e^0 {g(0) + g'(0)}

f'(0) = 1×(2+2) coz. g'(0)=2

f'(0) = 4