If f (x) = f (3x – 1) for f (x) = x2 – 4x +11, then x =
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The first one is,
If f(x) =f (3x-1),
We may have, x =3x-1
So, we get
X= 1/2.
The second one is,
We have, f(x) =x^2-4x+11
Then, we get
x^2-4x +11= ( 3x-1)^2 -4 (3x-1)+11
Or, 4 (3x-1) -4x = (3x-1)^2 -x^2
Or, 4 ( 3x-1-x) = ( 3x-1-x)(3x-1+x)
Or, 4 (2x-1) =(2x-1)(4x-1)
Or, (2x-1)( 4-4x+1)=0
Either,
2x-1=0 ie x=1/2
Or,
5-4x=0 ie. X = 5/4
Hence, form the above two method we get two possible value for x.
They are 1/ 2 and 5/4.
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