Question

if ∆f(x)=f(x-h)-f(x) then constant k,∆k equal​
(a) 1
(b) 0
(c) f(k)-f(0)
(d) f(x-k)-f(x)

Answer 1

Answer:

option c fkfogddfgggytttffffyhhy

Answer 2

If ∆f(x) = f(x - h) - f(x) then for the constant k , ∆k = 0

Given :

∆f(x) = f(x - h) - f(x)

To find :

For constant k , ∆k =

(a) 1

(b) 0

(c) f(k) - f(0)

(d) f(x - k) - f(x)

Solution :

Step 1 of 2 :

Write down the given formula

Here it is given that

∆f(x) = f(x - h) - f(x)

Step 2 of 2 :

Find the value of ∆k

Let f(x) = k where k is constant

Then f(x - h) = k

Thus we get

∆k

= ∆f(x)

= f(x - h) - f(x)

= k - k

$= 0$

Hence the correct option is (b) 0