If f(x) is a function which is odd and even simultaneously, then f(3) - f(2) is equal to
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The only functions which are both odd and even simultaneously are of the form:
f(x) = 0.
So, f(3) - f(2) = 0 - 0 = 0.
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Value of f(3) - f(2) is 0.
Given:
f(x) is a function which is odd and even simultaneously.
To Find:
Value of f(3) - f(2).
Solution:
According to the question,
f(-x) = f(x) (Since, it is an even function) -- eq1
f(-x) = -f(x) (Since, it is an odd function) --eq2
Equating equation 1 and 2 we get:
⇒f(x) = -f(x)
⇒2f(x) = 0
which implies that for all values of x f(x) = 0.
Therefore, f(3) = 0 & f(2) = 0.
Thus, f(3) - f(2) = 0.
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