If ƒ(x) is polynomial of degree 4 such that ƒ(1) = 1, ƒ(2) = 2, ƒ(3) = 3, ƒ(4) = 4 & ƒ(0) = 1
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If f(x) is the polynomial of degree 4 with leading co efficient one satisfying f(1) = 1 , f(2) =2 , f(3) =3 then [
f(0)+f(4)
f(−1)+f(5)
]
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Correct option is
C
1
f(x)=x for x∈1,2,3
f(x)−x=0 for x∈1,2,3
∴f(x)−x=(x−1)(x−2)(x−3)
f(x)=(x−1)(x−2)(x−3)+x
f(−1)=−25
f(5)=29
f(0)=−6
f(4)=10
f(0)+f(4)
f(−1)+f(5)
=
−6+10
−25+29
=
4
4
=1
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