If f(x)= log (secx+tanx) find f'(x)
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Step-by-step explanation:
y=log(secx+tanx)
differentiating w.r to x
dx
dy
=
dx
d
(log(secx+tanx))
=
secx+tanx
1
.(secxtanx+sec
2
x)
=
(secx+tanx)
secx(tanx+secx)
dx
dy
=secx
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