If f(x)=x^2-1,g(x)=x-2 find a, if gof(a)=1
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Heya!!
F(x) = x² - 1 And g(x) = x - 2
Put x = a we have
F(a) = a² - 1 And g(a) = a - 2
gof(a) = 1 ( Given )
g(f(a)) = 1 .... gof(x) = g(f(x))
g(a² - 1 ) = 1
a² - 1 - 2 = 1 ... By using g(x) = x - 2
a² = 4
a = ±2
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