if f(x)=x^2+1 then the value of f(-1)=
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f ( x ) = x² + 1
If f ( - 1), then
⇒ f ( - 1) = ( - 1 )² + 1
⇒ f ( - 1 ) = 1 + 1
⇒ f ( - 1 ) = 2
Hence, the value of f ( - 1 ) is 2.
If f ( - 1), then
⇒ f ( - 1) = ( - 1 )² + 1
⇒ f ( - 1 ) = 1 + 1
⇒ f ( - 1 ) = 2
Hence, the value of f ( - 1 ) is 2.
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