If f(x) = (x + 2)^2 – 1, what is the largest possible domain of f so that its inverse is also a function? explain by steps
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Given info : inverse of a function f (x) = (x + 2)² - 1 is also a function.
To find : largest possible domain of f.
Solution : here, f(x) = (x + 2)² - 1
⇒y = (x + 2)² - 1
⇒±√(y + 1) = x + 2
⇒x = -2 ± √(y + 1)
⇒f(y) = -2 ± √(y + 1) it will be function only when either f(y) = - 2 - √(y + 1) or -2 + √(y + 1) is inverse of f(x).
We know, range of inverse of f(x) = domain of f(x).
so, for large domain, range of inverse of f(x) must be large.
If we choose function f(y) = -2 - √(y + 1)
Domain y ≥ -1
⇒√(y + 1) ≥ 0
⇒-2 - √(y + 1) ≤ - 2
SO range of inverse of f(x) ≤ -2
But if we choose f(y) = -2 + √(y + 1)
range of f(y) ≥ -2
So, for domain of f(x) ≥ -2 , inverse of f is also a function.
Therefore the largest possible domain is [-2, ∞)
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