if f(x) = x^2+4 solve f(x+1)-f(x-1)-12=0
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Answer:
4x-12 -> x=3
Step-by-step explanation:
f(x+1)= (x+1)^2+4
x^2+2x+5
f(x-1)=(x-1)^2+4
x^2-2x+5
:-substituting values =
x^2+2x+5-(x^2-2x+5)-12=0
=4x-12=0
x=12/4
=3
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