Question

If f (x) = x 2 + 5 x - 1 , then f (2) + f (-3) =.​

Answer 1

Answer:

• \begin{gathered}f(x)= x^2-5x+1\\ \\f(2)= 2^2-5 \times 2+1 = 4-10+1=-5\\ \\f(-1)= (-1)^2-5(-1)+1=1+5+1=7\\ \\f( \frac{1}{3} )= (\frac{1}{3})^2-5(\frac{1}{3})+1=\frac{1}{9}-\frac{5}{3}+1 = \frac{1-15+9}{9}=-\frac{5}{9}\\ \\f(2)-f(-1)+f(1/3) = -5-7-\frac{5}{9}= \frac{-45-63-5}{9} =- \frac{113}{9} \end{gathered}
• f(x)=x
• 2
• −5x+1
• f(2)=2
• 2
• −5×2+1=4−10+1=−5
• f(−1)=(−1)
• 2
• −5(−1)+1=1+5+1=7
• f(
• 3
• 1
• )=(
• 3
• 1
• )
• 2
• −5(
• 3
• 1
• )+1=
• 9
• 1
• −
• 3
• 5
• +1=
• 9
• 1−15+9
• =−
• 9
• 5
• f(2)−f(−1)+f(1/3)=−5−7−
• 9
• 5
• =
• 9
• −45−63−5
• =−
• 9
• 113

Step-by-step explanation:

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Answer 2

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