Question

if f(x) =x^2-a^2/x2+a^2 and f(1)=1 then a=?

Answer 1

$\textbf{Answer}$

f(x) = x^2 - a^2/x^2 + a^2
where f(x) is a function that is dependant on the variable x.

$\textbf{Its given that f(1) = 1}$,
Which means that if we put the value of x as 1,then value of funtion becomes 1.

$\textbf{Lets put x = 1 in the function,}$

=> f(1) = 1^2 - a^2 / 1^2 + 1^2

=> 1 = 1 - a^2 + 1

=> a^2 = 2 - 1

=> a^2 = 1

=> a = √1

=> $\textbf{a = +1 or -1}$

$\textbf{Hope My Answer Helped}$
$\textbf{Thanks}$

Answer 2

f(x) = x^2 - a^2/x^2 + a^2
where f(x) is a function that is dependant on the variable x.

\textbf{Its given that f(1) = 1}Its given that f(1) = 1 ,
Which means that if we put the value of x as 1,then value of funtion becomes 1.

\textbf{Lets put x = 1 in the function,}Lets put x = 1 in the function, 

=> f(1) = 1^2 - a^2 / 1^2 + 1^2

=> 1 = 1 - a^2 + 1

=> a^2 = 2 - 1

=> a^2 = 1

=> a = √1

=> \textbf{a = +1 or -1}a = +1 or -1