If f(x)=x^2 and g(x)=2n+1 be two real functions find
i) (f+g)(x)
ii) (f-g)(x)
iii) (fg)(x)
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Answered by
1
Step-by-step explanation:
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Answered by
1
Answer:
Answer is given below,
Step-by-step explanation:
(f+g)(x)=f(x)+g(x)
=x
2
+2x+1
(f−g)(x)=f(x)−g(x)
=x
2
−(2x+1)
=x
2
−2x−1
(fg)(x)=f(x).g(x)
=x
2
(2x+1)
=2x
3
+x
2
(
g
f
)(x)=
g(x)
f(x)
(g(x)
=0)
=
2x+1
x
2
(x
=−
2
1
)
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