Question

If f(x) = x^2 g(x) and g(1) = 6, g'(1) = 3, find the value of f'(1).​

Answer 1

Answer:

15

Step-by-step explanation:

X^0.5 is root x

LET'S take

$g(x) = 6 \sqrt{x}$

Then g'(x) = 3/(x^0.5)

Now put the g(x) value in f(x)

And differentiate it and put value 1 in place of x

The answer will be 15

Hope it helps