If f(x) = (x+2)(x+4)(x+6)(x+8) + k is a perfect square then k =
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This type of question requires substituting.
(As we get 4th degree polynomial. We should use discriminant.)
We can expand the polynomial with having same quotient of x.
(x+2)(x+8) * (x+4)(x+6)
(x²+10x+16) * (x²+10x+24)
Now, as some part is repeated, we can let that 'T'.
(T+16) * (T+24) +k
T²+40T+(384+k)
This is a perfect square, then what is the discriminant value? 0.
D/4 = 400 -384 -k = -k +16 ∴ -k +16 =0
Therefore, k =16.
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