If f(x)=x^3+√2x^2+3√2x-1. Then evaluate f(2√2)
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Answered by
1
Answer:
Is the correct answer 24√2
[2√2]^3+√2[2√2]^2+3√2[2√2]-1
16√2+8√2+12-1
24√2+11
Hope it helps you
Answered by
0
Step-by-step explanation:
f(x)=x³+√2x²+3√2x-1
putting F(x)=2√2
Gives,2√2³+√2(2√2)²+3√2(2√2)-1
~16√2+8√2+12-1
=24√2+11
hope it help
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