Math, asked by aalijah8240, 1 year ago

If f(x)=x^3+√2x^2+3√2x-1. Then evaluate f(2√2)

Answers

Answered by Nayan987
1

Answer:

Is the correct answer 24√2

[2√2]^3+√2[2√2]^2+3√2[2√2]-1

16√2+8√2+12-1

24√2+11

Hope it helps you

Answered by SupriyaRastogi76
0

Step-by-step explanation:

f(x)=x³+√2x²+3√2x-1

putting F(x)=2√2

Gives,2√2³+√2(2√2)²+3√2(2√2)-1

~16√2+8√2+12-1

=24√2+11

hope it help

Mark As brainliest.....

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