Question

if the mass of block is 1 kg and a force of 10/root 3 n is applied horizontally on the block as shown in figure. the frictional force acting on the block is

Answer 1

Assuming the surface is flat, having no inclination.

Minimum Force (F) required to move the block= ¥N in horizontal direction

Where, ¥ is coffecient of friction

N is normal force which is equal to mg in this case, here m is mass of body and g is value of acceleration due to gravity.

So, F = ¥N = ¥mg = 1 × 10 × 5.77 is 57.7 Newton