if the mass of block is 1 kg and a force of 10/root 3 n is applied horizontally on the block as shown in figure. the frictional force acting on the block is
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Assuming the surface is flat, having no inclination.
Minimum Force (F) required to move the block= ¥N in horizontal direction
Where, ¥ is coffecient of friction
N is normal force which is equal to mg in this case, here m is mass of body and g is value of acceleration due to gravity.
So, F = ¥N = ¥mg = 1 × 10 × 5.77 is 57.7 Newton
Minimum Force (F) required to move the block= ¥N in horizontal direction
Where, ¥ is coffecient of friction
N is normal force which is equal to mg in this case, here m is mass of body and g is value of acceleration due to gravity.
So, F = ¥N = ¥mg = 1 × 10 × 5.77 is 57.7 Newton
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