Question

if f(x)=x^3+3x^2-2x+4,find f(-2)+f(2)-f(0)

Answer 1

f(x)=x³+3x²-2x+4
f(2)=2³+3(2)²-2(2)+4
=8+12-4+4
=20
f(-2)=(-2)³+3(-2)²-2(-2)+4
= -8+12+4+4
=12
f(0)=0³+3(0)²-2(0)+4
= 4

We need to find f(-2)+f(2)-f(0)
=12+20-4
=28

Answer 2

f(-2)=(-2)^3+3(-2)^2-2(-2)+4=-8+12-4+4=4
f(2)=(2)^3+3(2)^2-2(2)+4=8+12-4+4=20
f(0)=(0)^3+3(0)^2-2(0)+4=0+0-0+4=4
So,
f(-2)+f(2)-f(0)=4+20-4=20(Ans)
Hope it helps you..