Question

if f(x) = x^3-4x+1, then the value of f(2)+ f(-2) is _

Answer 1

Answer:

Given,

${\bf{\green{f(x)=x^3-4x+1}}}$

${\bf{\red{=>f(2)+f(-2)}}}$

${\bf{\blue{=>(2)^3-4(2)+1+(-2)^3-4(-2)+1}}}$

${\bf{\pink{=>8-8+1+(-8)+8+1}}}$

${\bf{\green{=>1-8+8+1}}}$

${\bf{\orange{=>1+1}}}$

${\bf{\blue{=>2}}}$

[

Answer 2

Hey mate here is your answer step-by-step...

Given....

f(x) = x^3 - 4x + 1

→ f(2) + f(-2)

→ 2^3 - 4(2) + 1 + (-2)^3 - 4 (-2) + 1

→ 8 - 8 + 1 + (-8) + 8 + 1

→ 1 - 8 + 8 + 1

→ 1 + 1

→ 2

I hope it will help you...

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