If f(x)=x^3+px^2+qx+30 is divisible by(x-5) and when it is divided by (x+6), the remainder is -396, then
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The sum of two numbers is 31.021 If one of them is 11.56 then the other number is
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ANSWER
The sum of two numbers =31.021
One of the numbers =11.560
Other number =31.021−11.560=19.461
So option A is the correct answer.
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