if f(x)= x raised to the power 4 + ax raised to the power 3 + bx raised to the power 2 +cx + d is a polynomial such that f(1) = 5 , f(2)= 10 , f(3) =15 f(4)=20 then find the value of f(5) and f(-5)
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Step-by-step explanation:
1)=10f(1)−10=0
f(2)=20⇒f(2)−20=0⇒f(2)−10×2=0
f(3)=30⇒f(3)−30=0⇒f(3)−10×3=0
g(a)=f(x)−10x=0
∴g(1)=f(1)−10=0
g(2)=f(2)−20=0
g(3)=f(3)−30=0
∴g(1)=g(2)=g(3)=0
⇒(x−1)(x−2)(x−3)dividesg(x)
g(x)=f(x)−10x=(x−t)(x−1)(x−2)(x−3)
f(x)=10x(x−t)(x−1)(x−2)(x−3
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