Math, asked by gyaneshkr195, 7 hours ago

If f(x) = |x| / x; x!= 0 ;then f(x) - f(-x) is equal to ​

Answers

Answered by BeAuTyBLusH
3

Answer:

One-one but not onto

Here, f:[0,∞)→[0,∞) i.e, domain is [0,∞) and codomain is [0,∞)

For one-one

f(x)= </p><p>1+x</p><p>x</p><p></p><p> </p><p>f </p><p>′</p><p> (x)= </p><p>(1+x) </p><p>2</p><p> </p><p>1

&gt;0,∀x∈[0,∞)

∴f(x) is increasing in this domain. Thus f(x) is one-one in its domain

For onto (we find range)

f(x)= </p><p>1+x</p><p>x</p><p></p><p>  i.e. y= </p><p>1+x</p><p>x</p><p>

⇒y+yx=x</p><p>⇒x= </p><p>1−y</p><p>y</p><p>

⇒x= </p><p>1−y</p><p>y

≥0 as x≥0

∴0≤y

=1 and y<1

∴ Range

= Codomain

∴f(x) is one-one but not onto

Answered by deepak9140
3

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