Question

If f(x) = (x2 - 1) and g(x) = (2x + 3) then (gof)(x) = 1​

Answer 1

$f(x) = ({x}^{2} - 1) \\ g(x) = (2x + 3) \\ gof = 1$

$(2( {x}^{2} - 1) + 3) =1\\ 2 {x}^{2} - 2 + 3 = 1 \\ 2 {x}^{2} + 1 = 1 \\ 2 {x}^{2} = 0 \\ {x}^{2} = 0 \\ x = 0$