Question

If f (x) =x2-5x+7 find f(2)+f(-1)+f(1/3)

Answer 1

Step-by-step explanation:

f(2)=4-10+7

=1

f(-1)= -2+5+7

= 10

f(1/3)= 2/3 -5/3 +7

= -3/3 +7

=-1+7

=6

=17

Answer 2

The correct answer is "175/9".

Step-by-step explanation:

$The \ given \ equation \ is:\\\\f(x)=x^2-5x+7\\\\f(2)+f(-1)+f(\frac{1}{3})=?\\\\Now,\\\\f(2)=(2)^2-5(2)+7\\\\f(2)=4-10+7\\\\f(2)=11-10\\\\f(2)=1\\\\and,\\\\f(-1)=(-1)^2-5(-1)+7\\\\f(-1)=1+5+7\\\\f(-1)=13\\\\and,\\\\f(\frac{1}{3})=(\frac{1}{3})^2-5(\frac{1}{3})+7\\\\f(\frac{1}{3})=\frac{1}{9} -\frac{5}{3} +7\\\\f(\frac{1}{3})=\frac{1-15+63}{9}\\\\f(\frac{1}{3})=\frac{49}{9}\\\\According \ to \ the \ queation,\\\\ =f(2)+f(-1)+f(1/3)\\\\=1+13+\frac{49}{9}\\\\=\frac{9+117+49}{9}\\\\=\frac{175}{9}$

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