Question

If f(x)=x³-2x²+3x-5,find the value of f(0) and f(1)​

Answer 1

Step-by-step explanation:

$f(0) = {0}^{3} - 2 \times {0}^{2} + 3 \times 0 - 5 \\ 0 - 0 + 0 - 5 \\ f(0) = - 5 \\ \\ f(1) = {1}^{3} - 2 \times {1}^{2} + 3 \times 1 - 5 \\ 1 - 2 + 3 - 5 \\ f(1) = - 3$

Answer 2

The answer $f(0)=-5, f(1)=-3$

Explanation: The given function is $f(x)=x^3-2x^2+3x-5$

Find the value of $f(0)$ and $f(1)$

Solution - Given function is $f(x)=x^3-2x^2+3x-5$

$f(0)=(0)^3-2(0)^2+3(0)-5$

$f(0)=-5$

$f(1)=(1)^3-2\times (1)^2 +3\times 1-5\\=1-2+3-5$

$=4-7\\=-3$

Hence, the value $f(0)=-5, f(1)=-3$

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