if f (x)=x3/a2-x2, then find the value of f'(a/2)
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Answer:
answer is a/6
Step-by-step explanation:
f'(a/2)= (a/2)^3/a^2-(a/2)^2
=a^3/8/a^2- a^2/4
=(a^3/8)/(4a^2 -a^2/4) (divide 8 by 4)
=a^3/2*3a^2
=a/6
hope this is the correct answer...here only u have to replace x from a/2.
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