Math, asked by blues34, 1 year ago

if f (x)=x3/a2-x2, then find the value of f'(a/2)​

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Answered by radha565
1

Answer:

answer is a/6

Step-by-step explanation:

f'(a/2)= (a/2)^3/a^2-(a/2)^2

=a^3/8/a^2- a^2/4

=(a^3/8)/(4a^2 -a^2/4) (divide 8 by 4)

=a^3/2*3a^2

=a/6

hope this is the correct answer...here only u have to replace x from a/2.

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