If f(x) = x³ + x² - ax + b is divisible by x² - x
then find the values of a and b.
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Step-by-step explanation:
X³ + x² -ax + b is divisible by x² - x or x(x -1)
it means x and (x -1) are the factors of x³ + x² -ax + b .
hence,. 0 and 1 are the zeros of x³ + x² -ax + b.
put x = 0
(0)³ + (0)² -a(0) + b = 0 => b = 0
put x = 1
(1)³ + (1)² - a(1) + b = 0
1 + 1 - a + b = 0
2 - a + 0 = 0 { after putting b = 0
a = 2
hence, a = 2 and b = 0
this answer is credited to @abhi178
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