If f(y) = log y, then f(y) + f(1/y) is equal to :
Answers
Answered by
8
given,
f(y)=logy
first find f(1/y)
f(1/y)= log(1/y)
= log1 - logy
= -log y
therefore,f(1/y)= -logy
now, f(y)+f(1/y) = logy - logy = 0
therefore, f(y)+f(1/y) = 0
f(y)=logy
first find f(1/y)
f(1/y)= log(1/y)
= log1 - logy
= -log y
therefore,f(1/y)= -logy
now, f(y)+f(1/y) = logy - logy = 0
therefore, f(y)+f(1/y) = 0
Answered by
0
Step-by-step explanation:
f(y) = log y
f(y) + f(1/y) = logy + log(1/y)=logy- logy=0
Similar questions