Question

If f(y) = $e^{y}$, g(y) = y; y > 0 and F(t) = $\int\limits^t_0 f(t-y)g(y)dy$ then
(a) F(t) = $te^{-t}$
(b) F(t) =$1-te^{-t}(1+t)$
(c) F(t) = $e^{t}-(1+t)$
(d) F(t) = $te^{-t}$

Answer 1

Hello mate ☺

Option B is correct one

Hope it helps u...❤

Answer 2

If f(y) = $e^{y}$, g(y) = y; y > 0 and F(t) = $\int\limits^t_0 f(t-y)g(y)dy$ then

(a) F(t) = $te^{-t}$

(b) F(t) =$1-te^{-t}(1+t)$✔

(c) F(t) = $e^{t}-(1+t)$

(d) F(t) = $te^{-t}$