Math, asked by smithi4349, 11 months ago

If first number is 1/12 less than third number and ratio of second and third number is 15:16 then first number is how much percent less than second number.
1) 28/9
2) 2.22%
3) 3.33%
4) 2.45%

Answers

Answered by sprao53413
2

Answer:

Please see the attachment

Attachments:
Answered by TanikaWaddle
3

option (2) is correct

The first number is 2.22% less than the second number

Step-by-step explanation:

Let the third number be x

then according to the question

first number = x- \frac{x}{12} = \frac{12x-x}{12} = \frac{11x}{12}

let the second number be y

ratio of second and third number is 15:16

i.e

y:x= 15:16

y= \frac{15x}{16}

then the difference between the first and second number

= \frac{15x}{16}-\frac{11x}{12}

= \frac{x}{48}

percentage of the first number less then the second number

= \frac{\frac{x}{48} }{\frac{15x}{16} }×100

= \frac{100x}{48}\times \frac{16}{15x}

= \frac{100}{45}

= 2.22%

hence ,

option (2) is correct

The first number is 2.22% less than the second number

#Learn more:

https://brainly.in/question/1423132

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